Remember that we can use some trigonometric identities to find relations between distances in a circle when the central angle is provided:
If we measure each distance in radius lengths, it is equivalent to take <em>r=1 </em>on those formulas.
A)
The terminal point's distance to the right of the center of the circle, measured in radius lengths, would be:
This distance is signed since it indicates an orientation, but we can ignore the sign if we are only interested on the value of the distance.
Then, such distance would be approximately 0.97 radii,
B)
Multiply the distance measured in radius lengths by the length of the radius to find the distance measured in cm:
C)
The terminal point's distance above the center of the circle can be calculated using the sine function:
Therefore, such distance is approximately 0.24 radii.
D)
Multiply the distance measured in radius length times the length of the radius to find the distance measured in cm:
The graph that shows the same end behavior as the graph of f(x) = 2x⁶ – 2x² – 5 is graph A.
<h3>
How to explain the graph?</h3>
In order to find the end behavior of the graph, we need to find the degree of the given function and the leading coefficient. The highest power of x is 6.
The leading coefficient is the coefficient of the highest power term. We have the highest power term is 2x⁶. The leading coefficient is 2 (Positive number)
Therefore, The graph that shows the same end behavior as the graph of f(x) = 2x⁶ – 2x² – 5 is graph A.
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(3,2);y=3x-2
The equation is in slope-intercept form...
y=mx+b
m is the slope.
b is the y-intercept, the value of y when x=0.
Slope is 3.
Any line parallel to this has the same slope.
Point-slope formula...
y-y1=m(x-x1)
y-2=3(x-3)
y-2=3x-9
Let's add 2 to both sides...
y-2+2=3x-9+2
y=3x-7
Let's check our work...
(3,2)
2=[(3)(3)]-7
2=9-7
2=2
The measures of x and y are 291.
The area of a triangle is .5*b*h = .5x^2
.5x^2 = 27 so
x^2 = 54
x = sqrt(54) = 7.3
