Answer: 7/15
Step-by-step explanation:
Answer:
v= 17
Step-by-step explanation:
Start with the given equation.
19v – 18 = 16 + 17v
Move -18 to the other side, and swap it's sign.
19v = 16 + 18 + 17v
Move 17v to the other side and swap it's sign.
19v - 17v = 16 + 18
Combine like terms.
2v = 34
Divide by 2v.
v = 17
Answer:
4/5
Step-by-step explanation:
32/40
16/20
8/10
4/5
Answer:
The equation of the parallel line is y = 5x + 11
Step-by-step explanation:
→ Parallel lines have same slopes and different y-intercepts
→ The slope-intercept form of the linear equation is y = m x + b, where
In our question
∵ The equation of the given line is y = 5x + 2
→ Compare it with the form above to find its slope
∴ m = 5
∵ The two lines are parallel
∴ Their slopes are equal
∴ The slope of the parallel line is 5
→ Substitute it in the form of the equation above
∴ y = 5x + b
→ To find the value of b substitute x and y in the equation by the
coordinates of any point on the line
∵ The line passes through point (-2, 1)
∴ x = -2 and y = 1
∵ 1 = 5(-2) + b
∴ 1 = -10 + b
→ Add 10 to both sides
∴ 1 + 10 = -10 + 10 + b
∴ 11 = b
→ Substitute value of b in the equation
∴ y = 5x + 11
∴ The equation of the parallel line is y = 5x + 11
Answer:
a) y = 3x+12
b) y-6 = 3(x+2)
Step-by-step explanation:
The equation of a line in slope-intercept form is expressed as y = mx+c
m is the slope or gradient
c is the intercept
We need to calculate the value of slope and intercept.
We will get the slope from the equation of line x+3y = 7
Rewriting the equation
3y = 7-x
y = 7/3 -x/3
M = -1/3
Since the equation if the unknown line is perpendicular to this line then Mm = -1 where m is the slope of the unknown line
m = -1/M
m = -1/(-1/3)
m = 3
To get c, we will substite the point given (-2,6) and the slope into the equation y = mx+c
6 = 3(-2)+c
6 = -6+c
c = 12
Substituting m= 3 and c = 12 into the standard form of the equation we have;
y = 3x+12 (This gives the required equation in its slope intercept form)
b) The standard form of a line is expressed as y-y1 = m(x-x1) where (x1,y1) are the points and m is the slope. On substituting the point {-2,6) and slope of 3 into this equation we will have:
y - 6 = 3(x-(-2))
y-6 = 3(x+2)
This gives the equation of the line in its standard form
