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fiasKO [112]
3 years ago
12

Carlos has $7 and he goes to the store and buys two granola bars at $2.50, one Gatorade at $2.50 and a pack of bubblegum for $.7

5 does Carlos have enough money explain your answer and use RACE
28 points!!!
Mathematics
1 answer:
sasho [114]3 years ago
3 0
No, Carlos doesn't have enough money. This is because he only has seven dollars to spend and his total would be $8.25. He wants to buy two granola bars which equal $5. Then you add $2.50 and the total would be $7.50. Then you add the pack of gum and the total could come out to $8.25.
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0, 7, 14, 21, next three terms
Nat2105 [25]

Answer:

28, 35, 42

Step-by-step explanation:

Adding by 7 every time. Also this is on the seven times table.

5 0
3 years ago
2 more questions thanks
sergey [27]
These are two questions and two answers.

1) Problem 17.

(i) Determine whether T is continuous at 6061.

For that  you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.

a) T(x) = 0.10x if 0 < x ≤ 6061

T (6061) = 0.10(6061) = 606.1

b) limit of Tx when x → 6061.

By the left the limit is the same value of T(x) calculated above.

By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)

⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10

Since both limits and the value of the function are the same, T is continuous at 6061.

(ii) Determine whether T is continuous at 32,473.

Same procedure.

a) Value at 32,473

T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26

b) Limit of T(x) when x → 32,473 from the right

Limit = 5360.26 + 0.26(x - 32,473) = 5360.26

Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.

(iii) If  T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.

2) Problem 18.

a) Statement Sk

You just need to replace n for k:

Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2

b) Statement S (k+1)

Replace

S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2

Simplification:

1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2

                 k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2

Do the operations on the left side and  you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.

With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.

4 0
3 years ago
Read 2 more answers
Please answer please question
Eva8 [605]

Answer:38

Step-by-step explanation:multiple

5 0
3 years ago
(Please respond quickly!)
ki77a [65]

Answer:

x=12

Step-by-step explanation:

we know that

A linear pair is two angles that are adjacent and form a line. The angle measure of a line is 180 degrees

In this problem we have that

(10x-20)^o+(6x+8)^o=180^o --- by supplementary angles (form a linear pair)

solve for x

(16x-12)=180

16x=180+12

16x=192

x=12

3 0
4 years ago
The track club runs the 50-yard dash. How many inches do they run?
Lady bird [3.3K]
Yd : in
1 : 36
50 : x
(cross multiply)

50(36) / 1 = 1800

Answer:
D) 1800 inches
8 0
3 years ago
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