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musickatia [10]
3 years ago
12

A gene exists in two alleles, which we will call B and b. The gene is 1123 bp in length, and the B and b alleles exhibit single

base pair differences at six different sites. If gene conversion changed the b allele into the B allele, which mechanism would you favor to explain the conversion
Biology
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

The below options will complete the question

Select one:

a. Gap repair synthesis

b. Mismatch repair

c. Direct repair

d. Nucleotide excision repair

Our answer is surely A.

a. Gap repair synthesis

Explanation:

Alleles of gene B differ by 6 bps and are seeming close to each other among the 1123 bp within the particular gene, favouring the gap repair synthesis.

In the gap repair synthesis, a double stranded break is formed at a homologous chromosome with a small part of the gene or the 6 bps of the recessive allele

being digested away.

Strand invasion and a D-loop formation is followed by the new region being occupied by the dominant B allele to yielding dominant B allele in both chromosomes.

The gap repair synthesis allows the 6bps to be converted to the dominant B from the recessive b when in proximity/being close together.

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The domestic cat genome contains 2.9×109 base pairs. The length of linker DNA in mammals is 50 base pairs. Approximately how man
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Answer:

Number of nucleosomes in 2.9 * 10^9bp is equal to 1.47 * 10^7

Explanation:

For wounding one nucleosome, total length of DNA required is equal to 146 bp

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Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length

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Thus, in 196bp length of DNA, the total number of nucleosomes is equal to 1

Thus, number of nucleosomes in 2.9 * 10^9bp is equal to

\frac{2.9* 10^9}{196} \\1.47 * 10^7

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