A function is said to have a vertical asymptote wherever the limit on the left or right (or both) is either positive or negative
infinity.
For example, the function f(x)= \frac{-3(x+2)}{x^2+4x+4} has a vertical asymptote at x=-2. For each of the following limits, enter either 'P' for positive infinity, 'N' for negative infinity, or 'D' when the limit simply does not exist.
\displaystyle{ \lim_{x\to -2^-} \frac{-3(x+2)}{x^2+4x+4} = }
\displaystyle{ \lim_{x\to -2^+} \frac{-3(x+2)}{x^2+4x+4} =}
\displaystyle{ \lim_{x\to -2} \frac{-3(x+2)}{x^2+4x+4} =}
1 answer:
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4 and 8::::::: because they have no variable u can add 4 and 8 which would be 12
Answer:
2 and 6 for the circles.
-18 for the square.
Step-by-step explanation:
-3 times a number is -6.

The number is 2.
2 times a number is 12.

The number is 6.
6 times -3.

The number is -18.
Answer:
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Answer:
-5 sorry if it's wrong. I tried.
-15 = -2.7 + t
add 2.7 to each side
-15+2.7 = -2.7+2.7 +t
-12.3 = t