Answer:
10.846 hours
Step-by-step explanation:
first you add all the calories= 1410 calories
then you divide 1410 calories by 130 (the calories you can burn in one hour)
your answer is 10.846 which means that it takes 10.846 hours to consume 1410 calories.
Answer:
Hey there!
This question is basically asking for the least common multiple, or LCM of the three numbers.
If it is a multiple of 10, it has to be a multiple of 5. Thus, the only thing we need to do now, is find the LCM of 10 and 7, which is 70.
Thus, your answer is 70.
Hope this helps :)
Answer:


Step-by-step explanation:
To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.
a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

we can substitute the value of sec(θ) in this equation:

and solve for for cos(θ)

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by
b) since right triangle is mentioned in the question. We can use:

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:
- length of the adjacent side = 1
- length of the hypotenuse = 52
we can find the third side using the Pythagoras theorem.




- length of the opposite side = √(2703) ≈ 51.9904
we can find the sin(θ) using this side:


and since 

Answer:
1(x - 2xz - 2xy + 4y²)
Step-by-step explanation:
I notice that no term all of them have. which means itbwill be factorised via 1.
1(x - 2xz - 2xy + 4y²)