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Lesechka [4]
3 years ago
10

What is the exact volume of the cylinder?

Mathematics
1 answer:
enyata [817]3 years ago
6 0

Answer:

Step-by-step explanation:

The formula for the volume of a cylinder is V = πr²h.  

Here, r = 5cm, and h = 15 cm, and so the volume is:

V = πr²h = π(5 cm)²(15 cm), or:

V = π(25 cm²)(15 cm) = 375π cm³, or approximately 1170 cm³

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Need help with my homework ​
Volgvan

Answer:

\displaystyle y=\frac{16-9x^3}{2x^3 - 3}

\displaystyle y=-\frac{56}{13}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3

Simplify the radical with the cube:

\displaystyle x^3=\frac{3y+16}{2y+9}

Multiply by 2y+9

\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)

Simplify:

\displaystyle x^3(2y+9)=3y+16

Operate the parentheses:

\displaystyle x^3(2y)+x^3(9)=3y+16

\displaystyle 2x^3y+9x^3=3y+16

Subtract 3y and 9x^3:

\displaystyle 2x^3y - 3y=16-9x^3

Factor y out of the left side:

\displaystyle y(2x^3 - 3)=16-9x^3

Divide by 2x^3 - 3:

\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}

ii) To find y when x=2, substitute:

\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}

\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}

\displaystyle y=\frac{16-72}{16- 3}

\displaystyle y=\frac{-56}{13}

\mathbf{\displaystyle y=-\frac{56}{13}}

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Answer:

I need a picture to solve...

Step-by-step explanation:

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I think that 52 is next number
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Answer:

$7.07

Step-by-step explanation:

35.35/5=7.07

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Find the sine of both angle A and angle B.
olchik [2.2K]
Sin = opposite/hyp

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Sin b = 24/26 = 12/13

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4 years ago
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