Y=mx+b
Y1-Y2/X1-X2
14-10/5-3 = 4/2 = 2
Plug in (3,10):
(10)=2(3)+b
Solve:
10=6+b
B=4
M=2
9514 1404 393
Answer:
a) V = 4w²h
b) SA = 4w² +10wh
c) SA = 4w² +37.5/w
d) C = 40w² +225/w
Step-by-step explanation:
The relevant formulas are ...
V = LWH
base area = LW
lateral area = H(2(L+W))
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a) The length is 4 times the width, so the volume is ...
V = (4w)(w)(h)
V = 4w²h
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b) The total surface area is the sum of the base area and the lateral area:
SA = base area + lateral area
SA = (4w)(w) + 2h(4w +w)
SA = 4w² +10wh
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c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...
15 = 4w²h
h = 15/(4w²)
Then the surface area is ...
SA = 4w² +10w(15/(4w²))
SA = 4w² +37.5/w
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d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:
C = 10(4w²) +6(37.5/w)
C = 40w² +225/w
400 should be the answer. Hope this helps!
Step-by-step explanation:
5x-6+7x+18=180
12x=180+6-18
12x=168
168÷12=14
X=14
for y
3y+11=7x+18(7×14+18)
3y+11=116
3y=116-11
3y=105
y= 35
There was only one car that went over the speed limit and it's car A (183). the other cars were all under and how i found this out was take 60 mph x hours n that's the miles they should of drove n that many hours if they are above it the miles will be higher.
