All categories

3 years ago

What are the values of the variable in 37 = 30 − x2?

1 answer:

7 0

30−x2=37

−x2+30=37
−x2+30−30=37−30
−x2=7
−x2−1=7−1
x2=−7
x=±√−7

Hoped I helped!

You might be interested in

Use a property to write an equivalent expression for 12 x (100 - 5). Which property did you use?

belka [17]

12 x 100 - 12 x 5

distributive property

8 0

3 years ago

Read 2 more answers

Please help and explain

mr_godi [17]

All but -1 <x <1
_____________

4 0

4 years ago

Adrian has 5 times as many stickers as Derrick. If Adrian has 325 stickers, how many stickers does Derrick have?

Arte-miy333 [17]

Answer: 65

Step-by-step explanation:

65 x 5= 325

5 0

3 years ago

Given the function below, select all the equalities that are true. f(x) = x2 + 3

nordsb [41]

Answer:

a&c

Step-by-step explanation:

because you can multiply to numbers and reach 0 or 2, but no number times another equals 7 and no number times 0 equals three (multiplicative identity of 0)

3 0

3 years ago

Determine whether the relation R on the set of all Web pages is reflexive, symmetric, antisymmetric, and/or transitive, where (a

xxMikexx [17]

Answer:

a) R is reflexive, R is not symmetric, R is not anti-symmetric, R is transitive.

b) R is reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

c) R is not reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

Step-by-step explanation:

(a, b) ∈ R if and only if everyone who has visited Web page a has also visited Web page b.

Obviously R is reflexive (aRa)

Everyone who has visited Web page a has also visited Web page a

R is not symmetric (aRb does not imply bRa)

If everyone who has visited Web page a has also visited Web page b does not mean that everyone who has visited Web page b has also visited Web page a

R is not anti-symmetric (aRb and bRa does not imply a=b)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page a does not mean the web pages are the same.

R is transitive (aRb and bRc implies aRc)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page c implies that everyone who has visited Web page a has also visited Web page c.

(a, b) ∈ R if and only if there are no common links found on both Web page a and Web page b.

R is obviously reflexive (aRa)

R is symmetric (aRb implies bRa)

if there are no common links found on both Web page a and Web page b, then there are no common links found on both Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there are no common links found on both Web page a and Web page b and there are no common links found on both Web page b and Web page a does not mean a and b are the same web page.

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a and c have a common link and b has no external links at all.

Then obviously (a,b)∈R and (b,c)∈R since b has no links, but (a,c)∉R because they have a common link.

(a, b) ∈ R if and only if there is at least one common link on Web page a and Web page b

R is not reflexive

If the web page a does not have any link at all, then a is not related to a.

R is symmetric (aRb implies bRa)

if there is at least one common link found on Web page a and Web page b, then there is at least one common link found on Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there is at least one common link found on Web page a and Web page b and there is at least one common link found on Web page b and Web page a does not mean the web pages are the same

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a has only two links L1 and L2, b has only two links L2 and L3 c has only two links L3 and L4.

Then (a, b) ∈ R since a and b have the common link L2, (b, c) ∈ R for b and c have the common link L3, but a and c have no common links, therefore (a,c)∉R

5 0

4 years ago