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Blababa [14]
3 years ago
10

What percent represents the part of the model shaded green. A.60% B.62.5%. C.66.7% D.75%

Mathematics
2 answers:
VLD [36.1K]3 years ago
4 0

Answer:

60%

Step-by-step explanation:

3/5 = 6/10 = 60%

Serjik [45]3 years ago
4 0

Answer:

A. 60%

Step-by-step explanation:

3/5 =30/50=60/100

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dusya [7]

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{(-2)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{4+2}{2}\implies \cfrac{6}{2}\implies 3

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2 years ago
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Simplify the algebraic expression (4b5 - 7) + (12b5 - 1)
ioda

Answer:16b square root of 5 -8

Step-by-step explanation:

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3 years ago
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you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
1 year ago
What is the slope of the line that passes through the pair of points (3,-9) and (17, 14)
Lilit [14]

Answer:

m = 1.643

Step-by-step explanation:

m = rise/run

= 23/-14

6 0
3 years ago
Which of the following equations has no solution?
fenix001 [56]

Answer:

The answer is the choices D which is the 3(2x - 4) = 6(x + 2)

Step-by-step explanation:

I hope that helps

4 0
2 years ago
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