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Anna11 [10]
4 years ago
6

Please help asap 25 pts

Mathematics
1 answer:
Kazeer [188]4 years ago
3 0
s=12\sqrt{4t}+10

for\ x=0\to y=12\sqrt{4\cdot0}+10=12\sqrt0+10=10\\for\ x=1\to y=12\sqrt{4\cdot1}+10=12\sqrt4+10=12\cdot2+10=34\\for\ x=4\to y=12\sqrt{4\cdot4}+10=12\sqrt{16}+10=12\cdot4+10=58\\for\ x=6\to y=12\sqrt{4\cdot6}+10=12\cdot2\sqrt6+10=24\sqrt6+10\approx69\\for\ x=10\to y=12\sqrt{4\cdot10}+10=12\cdot2\sqrt{10}+10=24\sqrt{10}+10\approx86\\for\ x=12\to y=12\sqrt{4\cdot12}+10=12\cdot4\sqrt3+10=48\sqrt3+10\approx93

\underline{x|\ 0|\ 1\ |\ 4|\ 6\ |10|12|}\\y|10|34|58|69|86|93|

\text{The graph in attachment}

\boxed{Answer:\ about\ \$93,000}

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121 km\hr

Step-by-step explanation:

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In the line y - 3 = -2 (x+5), which of the following are true?
blsea [12.9K]

Answer:

Options a, d and e

Step-by-step explanation:

We check the validity of each of the options.

Kindly note that we can express the equation fully and we have;

y-3 = -2x-10

y = -2x -10 + 3

y = -2x -7

So let’s now evaluate the options.

(a) Insert the value of x at this point, if it gives the value of y, then it’s on the line

the value of x to insert is -5 here.

Thus ; y = -2(-5)-7 = 10-7 = 3

since y is 3, then it is on the line

(b) same as a

insert x = 5

y = -2x-7

y = -2(5) -7

y = -10-7 = -17

This is definitely not on the line as the value of y gotten does not correlate with what was given

c. To get this , compare with the standard form of

y = mx + c

where m is slope

Here our m is -2 , so this is definitely wrong

d) From above , we can see that this is correct

e) compare this with y = mx + c

c is our intercept and this is equal to -7 which makes this option also correct

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I REALLY NEED HELP WILL GIVE EVERYTHING GOOD IF YOU HELP ON 2 MORE
DerKrebs [107]

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VashaNatasha [74]
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