What is the surface area of the cone below?

Mathematics

1 answer:

liberstina [14]3 years ago

4 0

For this case we have that by definition, the surface area of a cone is given by:

$SA = \pi * r * S + \pi * r ^ 2$

Where:

SA: It is the surface area

A: It's the radio

S: It's slant height

Then, replacing the values of the figure in the formula we have:

$SA = \pi * 6 * 15 + \pi * 6 ^ 2\\SA = 90 \pi + 36 \pi\\SA = 126 \pi \ units ^ 2$

ANswer:

Option A

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wariber [46]

Answer:

The answer to this question is given below in the explanation section.

Step-by-step explanation:

The table shows three different recipes. In this question, it is asked that will all the recipes taste same. To obtain the answer to this question, first, we measure the taste of each recipe in terms of calculating the ratio.

Water ............................. Cups

1 ............................. 3

4 ............................. 12

6 ............................. 18

1. The fraction of the first recipe is 1/3 so the ratio is 1:3(water to cup)

2. The fraction of the second recipe is 4/12

which can be simplified as 4/12=1/3 so the ratio is 1:3(water to cup)

3. The fraction of the third recipe is 6/18

which can be simplified as 6/18 = 3/9 = 1/3 so the ratio is 1:3(water to cup).

So based on the above answer, all recipes taste the same.

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5 0

3 years ago

Given: Quadrilateral DEFG

nadya68 [22]

We know that
The inscribed angle Theorem states that t<span>he inscribed angle measures half of the arc it comprises.
</span>so
m∠D=(1/2)*[arc EFG]
and
m∠F=(1/2)*[arc GDE]

arc EFG+arc GDE=360°-------> full circle

applying multiplication property of equality
(1/2)*arc EFG+(1/2)*arc GDE=180°

applying substitution property of equality
m∠D=(1/2)*[arc EFG]
m∠F=(1/2)*[arc GDE]
(1/2)*arc EFG+(1/2)*arc GDE=180°----> m∠D+m∠F=180°

the answer in the attached figure