Hello,
Let's put the 6 houses on side: 6P9=9*8*7*6*5*4/6! = 84
For each choice there are 3! choices pour the other side
84*3!=504
23. 5+9((9)-8)2, 5+9(1)2, 5+18=23

thus, the best car is car B,because it can tavel 29 miles with only one gallon,andcar A can only travel 28 miles with one gallon.
Using the information given above, the sampling distribution of the sample proportion of 100-ohm gold-band is 2.
- <em>Sampling distribution of proportion, P = 2% = 0.02 </em>
- <em>Sample size, n = 100</em>
<u>The sampling distribution of the sample proportion can be calculated thus</u>:
- <em>Distribution of sample proportion = np</em>
Distribution of sample proportion = (100 × 0.02) = 2
Therefore, there is a probability that only 2 of the samples will have resistances exceeding 105 ohms.
Learn more : brainly.com/question/18405415
Answer:
25.59
Step-by-step explanation:
The first thing that you will do is solve parenthesis (remember PEMDAS).
(32.45-4.8) - 2.06
(27.65) - 2.06
Then do the subtraction.
(27.65) - 2.06=
25.59
Hope this helps!