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4 years ago

Solve the System. Give answer as (x, y, z). 1x –3y+4z=12 2x+3y-5z=-10 - 4x + 3y + 6z=22

1 answer:

3 0

(2,2,4)
Hint: Use row operations to identify the values for (X,Y,Z) and check on a graphing calculator. It’s exhausting, but you can check using the RREF tool. :)
Hope that helps.

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Imagine that a graph pf a function rule intersects the y-axis at some point. What do the coordinates of the intersection

suter [353]

Given:

A graph of a function rule intersects the y-axis at some point.

To find:

What do the coordinates of the intersection indicate.

Solution:

We know that, x-values are input values and y-values are output values.

At y-axis the value of x is always 0.

If a function rule intersects the y-axis at some point, then the point represents the y-value when x=0.

So, it indicates the function's output when the input is 0.

Therefore, the correct option is d.

6 0

3 years ago

Simplify negative 5 and 1 over 4 − negative 7 and 1 over 2 . Which of the following is correct?

Makovka662 [10]

- 5 1/4 - (- 7 1/2) =
- 21/4 + 15/2 =
-21/4 + 30/4 =
9/4 or 2 1/4 <==

5 0

4 years ago

Read 2 more answers

What is an equation of the line that passes through the point (8,-7)(8,−7) and is parallel to the line 5x+4y=165x+4y=16?

gizmo_the_mogwai [7]

Answer:

The equation of line that passes through the point (8,-7) and is parallel to the line 5x+4y=16 is $\mathbf{y=-\frac{5}{4}x+3}$

Step-by-step explanation:

We need to write an equation of the line that passes through the point (8,-7) and is parallel to the line 5x+4y=16.

The equation will be of form $y=mx+b$ where m is slope and b is y-intercept.

Finding slope of the line:

Since both the lines are parallel, and we know that parallel lines have same slope.

The slope of given line $5x+4y=16$ can be found by writing in slope-intercept form $y=mx+b$

$5x+4y=16\\4y=-5x+16\\y=-\frac{5}{4}x+16$

Comparing with $y=mx+b$ the slope m is: $m=-\frac{5}{4}$

So, the slope of required line is: $m=-\frac{5}{4}$

Now, finding y-intercept b

y-intercept can be found using slope $m=-\frac{5}{4}$ and point (8,-7)

$y=mx+b\\-7=-\frac{5}{4}(8)+b\\-7=-5(2)+b\\-7=-10+b\\b=-7+10\\b=3$

So, we get y-intercept: b=3

Now, the equation of required line having slope $m=-\frac{5}{4}$ and y-intercept b=3 is:

$y=mx+b\\y=-\frac{5}{4}x+3$

So, the equation of line that passes through the point (8,-7) and is parallel to the line 5x+4y=16 $\mathbf{y=-\frac{5}{4}x+3}$

4 0

3 years ago

Need help ASAP!!!!!!

pogonyaev

Answer:

Simplifying the expressions:

14. $\frac{2 \pm \sqrt{36}}{4}$

i.e. $\frac{2 \pm 6}{4}$ = $\frac{8}{4}$ and $\frac{-4}{4}$ = 2 and -1.

15. $\frac{-12 \pm \sqrt{0}}{4}$

i.e. $\frac{-12 \pm 0}{4}$ = $\frac{-12}{4}$ = -3

16. $\frac{-3 \pm \sqrt{25}}{8}$

i.e. $\frac{-3 \pm 5}{8}$ = $\frac{-8}{8}$ and $\frac{2}{8}$ = -1 and $\frac{1}{4}$

17. $\frac{4 \pm \sqrt{200}}{12}$

i.e. $\frac{4 \pm 10\sqrt{2}}{12}$ = $\frac{2 \pm 5\sqrt{2}}{6}$

18. $\frac{-12 \pm \sqrt{204}}{2}$

i.e. $\frac{-12 \pm 2\sqrt{51}}{2}$ = $-6 \pm \sqrt{51}$

19. $\frac{6 \pm \sqrt{-264}}{6}$

i.e. $\frac{6 \pm 2i\sqrt{66}}{6}$ = $1 \pm \frac{i\sqrt{66}}{3}$

20. $\frac{-3 \pm \sqrt{25}}{2}$

i.e. $\frac{-3 \pm 5}{2}$ = $\frac{-8}{2}$ and $\frac{2}{2}$ = -4 and 1.

7 0

3 years ago

What is 808 rounded to the nearest ten.

Nataly_w [17]

Answer: 810???

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers