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3 years ago

What is 808 rounded to the nearest ten.

Mathematics

2 answers:

Nataly_w [17]3 years ago

4 0

Answer: 810???

Step-by-step explanation:

nordsb [41]3 years ago

3 0

Answer:

Step-by-step explanation:

You would round up: 810.

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Answer:

11 and 1/4 yards of ribbon

Step-by-step explanation:

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Use the definition of the derivative as a limit to find the <br> derivative f′ where f(x)= √ x+2.

MA_775_DIABLO [31]

Step-by-step explanation:

If the equation is

$\sqrt{x + 2}$

Then, here is the answer.

The definition of a derivative is

$\frac{f(x + h) - f(x)}{h}$

Also note that we want h to be a small, negligible value so we let h be a value that is infinitesimal small.

So we get

$\frac{ \sqrt{x + h + 2} - \sqrt{x + 2} }{h}$

Multiply both equations by the conjugate.

$\frac{ \sqrt{x + h + 2} - \sqrt{x + 2} }{h} \times \frac{ \sqrt{x + h + 2} + \sqrt{x + 2} }{ \sqrt{x + h + 2} + \sqrt{x + 2} } = \frac{x + h + 2 - (x + 2)}{h \sqrt{x + h + 2} + \sqrt{x + 2} }$

$\frac{h}{h \sqrt{x + h + 2} + \sqrt{x + 2} }$

$\frac{1}{ \sqrt{x + h + 2} + \sqrt{x + 2} }$

Since h is very small, get rid of h.

$\frac{1}{ \sqrt{x + 2} + \sqrt{x + 2} }$

$\frac{1}{2 \sqrt{x + 2} }$

So the derivative of

$\frac{d}{dx} ( \sqrt{x + 2} ) = \frac{1}{2 \sqrt{x + 2} }$

Part 2: If your function is

$\sqrt{x} + 2$

Then we get

$\frac{ \sqrt{x + h} + 2 - ( \sqrt{x} + 2) }{h}$

$\frac{ \sqrt{x + h} - \sqrt{x} }{h}$

$\frac{x + h - x}{h( \sqrt{x + h} + \sqrt{x}) }$

$\frac{h}{h( \sqrt{x + h} + \sqrt{x} ) }$

$\frac{1}{ \sqrt{x + h} + \sqrt{x} }$

$\frac{1}{2 \sqrt{x} }$

$\frac{d}{dx} ( \sqrt{x} + 2) = \frac{1}{2 \sqrt{x} }$

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3 years ago

Determine the angle at the centre of a circle with radius 12.0 cm for an arc length of of 21.0 cm.

nata0808 [166]

Answer:

$\theta=\dfrac{7}{4}\ \text{radian}$

Step-by-step explanation:

We have,

Radius of the circle is 12 cm

Arc length, l = 21 cm

It is required to find the central angle of the circle. The formula for the length of an arc of a circle is :

$l=r\times \theta$

$\theta$ is central angle

$\theta=\dfrac{l}{r}\\\\\theta=\dfrac{21}{12}\\\\\theta=\dfrac{7}{4}\ \text{radian}$

So, the angle at the centre of the circle is $\dfrac{7}{4}\ \text{radian}$ .

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How did astronomers determine where Earth is located within the Milky Way?

Igoryamba

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