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Natalija [7]
3 years ago
11

Need help on this problem

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0
The answer to the question

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Someone help need this done right now I’ll mark u brainliest
Ad libitum [116K]

Answer:

89 meters

Step-by-step explanation:

We know it's 9 + "the height of the triangle".

Fortunately, the height of the triangle (let's call it y) can be computed from:

y^2 + 18^2 = 82^2 (Pythagoras theorem).

y^2 = 82^2 - 18^2 = 6724 - 324 = 6400

y = 80 (or y = -80 but it doesn't make sense in geometry).

so x = y + 9 = 89;

3 0
3 years ago
Can anyone help me with this question
faust18 [17]

Answer:

Step-by-step explanation:

Like your other question, let's break it down systematically

6x + 9y - 9(6x - 3y + 8z)

Use the distributive property

6x + 9y - <u>9(6x - 3y + 8z)</u>

6x + 9y - 54x - 27y + 72z

Match like terms

6x - 54x = -48x

9y - 27y = -18y

72z - 48x - 18y

6 0
3 years ago
What is the value of x in the triangles to the right?<br> A. 9<br> B. 12<br> C. 15<br> D. 17.5
Gnom [1K]
The answer for this is B
8 0
3 years ago
Are 7xy and 2yx like terms
Vanyuwa [196]

Answer: no, 7xy and 2xy are not like terms

3 0
3 years ago
Read 2 more answers
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
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