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kondor19780726 [428]
4 years ago
13

Jorge has his own business as a painter. The amounts he made in the last five months are shown below. Find the mean, median, and

range of the data
$2426 52463 51451 $2154 $1119
Mathematics
1 answer:
deff fn [24]4 years ago
6 0

I'm gonna assume that the 5s are $.

To find the mean, add all the numbers, then divide by the number of data points (5).

(2426+2463+1451+2154+1119)/5 = 1922.6

To find the median, put the data in order from least to greatest, then find the middle data point.

1119 1451 2154 2426 2463

To find the range, subtract the largest from the smallest:

2463-1119 = 1344

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Answer: -4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

Step-by-step explanation:

Given

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t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15

Using completing the square method

y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)

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