Answer:
If the kid walks for the dotted line, the distance is 36ft.
Now, you can see that this is a triangle rectangle, then we must have that:
x^2 + (x + 6)^2 = 36^2 (the Pythagorean theorem)
Now we must solve this for x.
x^2 + x^2 + 2*6*x + 36 = 36^2
2*x^2 + 12*x -1260 = 0
The solutions for this equation are:
![x = \frac{-12 +-\sqrt{12^2 +2*4*1260} }{2*2} = \frac{-12 +-101.1}{4}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-12%20%2B-%5Csqrt%7B12%5E2%20%2B2%2A4%2A1260%7D%20%7D%7B2%2A2%7D%20%3D%20%5Cfrac%7B-12%20%2B-101.1%7D%7B4%7D)
the solutions are:
x = (-12 - 101.1)/4 = -28.78
x = (-12 + 101.1)/4 = 22.3
Then we have x = 22.3 ft
The lenght of the path following the cathetus is:
D = x + x + 6 = 2*22.3ft + 6ft = 50.6ft
Then the difference between the distances is:
Diff = 50.6ft -36ft = 14.6ft
Let the smaller odd integer be x and the larger be x + 2.
![x + x + 2 \leqslant 46 \\ 2x + 2 \leqslant 46 \\ 2x \leqslant 44 \\ x \leqslant 22 \\ x = 21](https://tex.z-dn.net/?f=x%20%2B%20x%20%2B%202%20%5Cleqslant%2046%20%5C%5C%202x%20%2B%202%20%5Cleqslant%2046%20%5C%5C%202x%20%5Cleqslant%2044%20%5C%5C%20x%20%5Cleqslant%2022%20%5C%5C%20x%20%3D%2021)
21, 23
![\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}](https://tex.z-dn.net/?f=%5Cmathfrak%7B%5Chuge%7B%5Cpink%7B%5Cunderline%7B%5Cunderline%7BAnSwEr%3A-%7D%7D%7D%7D%7D)
Actually Welcome to the Concept of the Factors.
1.) x^2-3x-10 = (x-5) (x+2)
2.)x^2-3x-18 = (x-6) (x+3)
Answer:
56 is your answer
Step-by-step explanation:
336/6=(56×3)/3=56