Given:
The right triangular prism.
Height of prism = 28 in.
Hypotenuse of base = 25 in.
leg of base = 24 in.
To find:
The lateral surface area of the prism.
Solution:
Pythagoras theorem:

Using Pythagoras theorem in the base triangle, we get




The perimeter of the triangular base is:


Lateral area of a triangular prism is:

Where, P is the perimeter of the triangular base and h is the height of the prism.
Putting
in the above formula, we get


Therefore, the lateral area of the prism is 1568 in².
Given:
The vertex of a triangle MNP are M(-4, 6), N(2, 6), and P(-1, 1).
The rule of dilation is:
The image of triangle MNP after dilation is M'N'P'.
To find:
The coordinates of the endpoints of segment M'N'.
Solution:
The end points of MN are M(-4, 6) and N(2, 6).
The rule of dilation is:
Using this rule, we get
And,
The endpoints of M'N' are M'(-6, 9) and N'(3, 9).
Therefore, the correct option is B.
Answer:
yay u got your answer:))
but seriously what is your question?:))
GMC Answer : 3 because of there
It is 31%.
To explain, you have to just have to multiply 0.31 by 100, and then add a percentage sign.