I need help with my math homework!!!!!! geometry

Mathematics

1 answer:

Nana76 [90]3 years ago

7 0

The answer to this question is 23. To solve this, write an equation to solve x, This equation will be 12x + 6 = 78. Subtract 6 from both sides to get 12x = 72. Next, divide both sides by 12 to get x = 6. Now, just plug in x for both angles. 4 times 6 is 24, minus 1 is 23. To check this, make sure the other angle (angle NRP) equals 55. 8 times 6 equals 48, plus 7 equals 55. I hope this helped! Could I possibly get brainliest?

You might be interested in

At which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptote? Check all that apply

pychu [463]

vertical asymptotes: x=-4 , x=1 , x=4

6 0

3 years ago

Read 2 more answers

A pie tin has an area of 81 pi square inches. Which choice below is closest to its

Brrunno [24]

Answer:

can i have the choices

Step-by-step explanation:

7 0

3 years ago

Graph g(x) = –2x – 3

Luba_88 [7]

Answer:

The slope would be -2 with a y-intercept of (0, -3).

I hope this helped to answer your question.

4 0

3 years ago

Patrick works a 40-hour week at $10.70 an hour with time and a half for overtime. Last week he worked 45 hours. What were his to

MA_775_DIABLO [31]

D. $
481.15 there you go

3 0

3 years ago

What is the smallest positive integer for x so that f(x)=200(2)* is greater than the value of g(x)=500x+400?

Goshia [24]

We have to functions, namely:

$f(x)=200(2)^{x} \ and \ g(x)=500x+400$

So the problem is asking for the smallest positive integer for $x$ so that $f(x)$ is greater than the value of $g(x)$ , that is:

$f(x)\ \textgreater \ g(x) \\ \therefore 200(2)^{x}\ \textgreater \ 500x+400$

Let's solve this problem by using the trial and error method:

$for \ x=1 \\f(1)=400 \\ g(1)=900 \\ Then \ f(1) \ \textless \ g(1) \\ \\ \\ for \ x=2 \\f(2)=800 \\ g(2)=1400\\ Then \ f(2)\ \textless \ g(2) \\ \\ \\ for \ x=3 \\f(3)=1600 \\ g(3)=1900 \\ Then \ f(3)\ \textless \ g(3) \\ \\ \\ for \ x=4 \\f(4)=3200 \\ g(4)=2400 \\ \boxed{Then \ f(4)\ \textgreater \ g(4)}$

So starting $x$ from 1 and increasing it in steps of one we find that:

$f(x)>g(x)$

when $x=4$

That is, the smallest positive integer for $x$ so that the function $f(x)$ is greater than $g(x)$ is 4.

8 0

3 years ago