It would be 2u3+4u2-2u-4u2-8u+4= 2u3-10u+4
22 touchdowns and 13 field goals
Answer:
~
~
Step-by-step explanation:
From the question we are told that:
Price of 20TVs per week
Marginal price-demand function 
Generally the The Marginal price function is mathematically given by
Therefore the equation when the demand is 20 TVs per week at $150 per TV

Giving

Therefore the Price when the demand is 100 TVs per week

