Answer:
Multiply the top equation by -3 and the bottom equation by 2
Step-by-step explanation:
Given <u>system of equations</u>:

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>. To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.
<u>To eliminate the </u><u>variable y</u>:
Multiply the top equation by -3 to make the coefficient of the y variable 6:

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

Add the two equations together to <u>eliminate y</u>:

<u>Solve</u> for x:


<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:





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Answer:
a^4·m^4·n^8
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)(a^c) = a^(b+c)
__
m^2n^3 aanm^2a^2n^4
= a^(1+1+2)·m^(2+2)·n^(3+1+4)
= a^4·m^4·n^8
It'll be the opposite reciprocal in front of the X like instead of 3 it will be -1/3 so flip it and change the sign
If p = 2, insert the value of p.
2^3 = 2 x 2 x 2 = 4 x 2 = 8
so p^3 = 8