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stealth61 [152]
3 years ago
8

What is the GCF of 77 and 56?

Mathematics
2 answers:
AveGali [126]3 years ago
5 0
The GCF is seven. 7*11 and 7*8
faltersainse [42]3 years ago
5 0
The gcf of 77 and 56 is 7
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The whole numbers from 10-12 are paired with their factors explain why this pairing doesnt describe a function
myrzilka [38]

Answer:

As given whole numbers from 10 - 12 are paired with their factors.

factor of ,10=1,2,5,10 → (10,1),(10,2),(10,5)(10,10)

factor of 11=1, 11 → (11,1),(11,11)

factor of 12=1,2,3,4,6,12→ (12,1),(12,2),(12,3),(12,4),(12,6),(12,12)

As we know for an ordered pair to be function Every element in the domain must have a unique image, i.e it can't have more than one image.

→ As element 10, have four images,which are 1,2,5,10 so it can,t be a function.

Similarly element 11 have two images 1,11 so it can't be a function.

Element 12 have six images 1,2,3,4,6,12, so it also can't be written as function.





8 0
3 years ago
Two or more ratios that shows the same value are called​
Zinaida [17]

Answer:

equivalent ratios.

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
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What is the simplified form of the following expression? 5sqrt 8-sqrt18-2sqrt2
spayn [35]

Answer:

5 sqrt2.

Step-by-step explanation:

sqrt8 = sqrt4 * sqrt2 = 2 sqrt2

sqrt18 = sqrt9 * sqrt2 = 3 sqrt2

So simplifying:

5sqrt 8 - sqrt18 - 2 sqrt2

= 5*2sqrt2 - 3 sqrt 2 - 2 sqrt2

= 10 sqrt2 - 5 sqrt2

= 5 sqrt2 (answer).

7 0
3 years ago
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PLEASE HELP URGENT
ad-work [718]
Pick - d. 51 minutes
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3 years ago
At any point in time, there could be bicycles, tricycles, and
Aleksandr-060686 [28]

Answer:

There may be 1 or 3 tricycles in the parking lot.

Step-by-step explanation:

Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:

13 x 4 + 1 x 3 + 1 x 2 = 57

11 x 4 + 1 x 3 + 3 x 2 = 53

10 x 4 + 3 x 3 + 2 x 2 = 53

8 x 4 + 5 x 3 + 2 x 2 = 51

10 x 2 + 1 x 3 + 4 x 4 = 39

9 x 3 + 1 x 2 + 5 x 4 = 49

Therefore, there may be 1 or 3 tricycles in the parking lot.

6 0
3 years ago
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