X2+5x+y2-y=-2 X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2 (x+5/2)^2+(y-1/2)^2-13/2=-2 (x+5/2)^2+(y-1/2)^2=9/2 So centre =(-5/2,1/2) Radius=(9/2)^(1/2)
In order to find the slop it is probably best to put the equation in y=mx+b form. This means to get y by itself on one side. 24x-9y=63 will then become -9y=63-24x in which y has been isolated. Then you should divided by -9 to get the final form: y=24x/9 -63/9. Now you can get the slope of the perpendicular line by taking the slope of the original equation and finding its reciprocal which is -9/24x. This is your answer.
