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Alona [7]
3 years ago
12

Can someone please help!!! Sec. 12.7 #78

Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0
Question please I can’t see 1
gizmo_the_mogwai [7]3 years ago
3 0
Theres nothikg to see
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Can someone help me with these both
Anna [14]
Hello,
so all you have to do is match the abbreviations to the triangles. The abbreviations stand for what is the SAME in both triangles, denoted by similar markings on equal sides and angles.

Abbreviations:
SSS = Side-Side-Side
SAS = Side-Angle-Side
ASA = Angle-Side-Angle
AAS = Angle-Angle-Side
HL = Hypotenuse-Leg

* Note - the angle side angle must go around the triangle in that order. ASA has the side BETWEEN the congruent angles.. SSA does NOT work.

(9.) ASA
(10.) AAS
(11.) SSS
(12.) No way to tell if congruent. (only 3 angles no side)
(13.) ASA
(14.) SAS
(15.) HL

7 0
3 years ago
Given that triangle ABC is a right triangle, select a set of possible side length measures.
ad-work [718]

You didn't supply any rules or constraints so.... 1 in., 1 in., and 1 in.

You can use the Pythagorean Theorem to check if the side lengths are appropriate.

a^2 + b^2 = c^2

1^2 + 1^2 = 1^2 –this is true.

5 0
4 years ago
Read 2 more answers
In a wrestling contest, a wrestler needs a winning percentage of at least 70% to qualify for round 2. sam lost 3 out of 12 match
algol [13]
He won about 25% because 6/12 would be 1/2 and 3 is 1/2 of 6 or a 1/4 so 25%
8 0
4 years ago
7x9=7x5+7x= <br> Please help i’m on a test
mariarad [96]
I can’t see the photo sorry
7 0
3 years ago
What is the solution to the equation? (-9x+5)^1/2=(3+4x)1/2
Phoenix [80]
<span>x in (-oo:+oo)

((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2

((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0

(5-9*x)/2-((4*x+3)/2) = 0

(5-9*x)/2+(-1*(4*x+3))/2 = 0

5-1*(4*x+3)-9*x = 0

2-13*x = 0

(2-13*x)/2 = 0

(2-13*x)/2 = 0 // * 2

2-13*x = 0

2-13*x = 0 // - 2

-13*x = -2 // : -13

x = -2/(-13)

x = 2/13

x = 2/13</span>
4 0
4 years ago
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