Answer:
The answer is 3 , 1 , 2 .
Step-by-step explanation:
I will give an example.
e.g.
x² + 3x + 2
Step 3 :
Set the equation equal to zero :
x² + 3x + 2 = 0
Step 1 :
Completely factor the equation :
x² + x + 2x + 2 = 0
x(x+1) + 2(x+1) = 0
(x+2)(x+1) = 0
Step 2 :
Set each factor equal zero and then solve for the variable :
(x+2)(x+1) = 0
x + 2 = 0
x = -2
x + 1 = 0
x = -1
Answer:
256
Step-by-step explanation:
I judt know I don't know hoet to explain sorry hope it helps
(1) For the parabola on the bottom row, the domain would be R and the range would be y ≥ -5
(2) For the hyperbola on the bottom row, the domain would be R\{3} (since there is an asymptote at x = 3) and the range would be R\{4} (since there is an asymptote at y = 4)
(3) For the square root function on the bottom row, the domain would be x ≥ -5 and the range would be (-∞, -2]
(4) For the function to the very right on the bottom row, the domain would be R and the range would be (-∞, -3]
Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
Answer:
$104
Step-by-step explanation:
If the cost in the store is x we can write:
75%x = 78
0.75x = 78
x = 78 / 0.75 = 104
