3d - e =7
d + e = 5
-------------
4d / = 12
d=12:4
d=3
3+e=5
e=5-3
e=2
the solution is (3,2)
The distance traveled by first car is 50t + 100.
The distance traveled by second car is 70t.
The distance between the two cars after time, t is d = 100 - 20t.
The ratio of the distance traveled by the cars is (70t) / (50t + 100).
<h3>
Distance traveled by each vehicle is calculated as follows;</h3>
The distance traveled by each vehicle at the given time is calculated as follows;
<h3>Distance traveled by first car</h3>
D₁ = speed x time
D₁ = 50(t + 2)
D₁ = 50t + 100
<h3>Distance traveled by the second car</h3>
D₂ = 70t
<h3>Distance between the two cars after time, t</h3>
d = D₁ - D₂
d = (50t + 100) - 70t
d = 100 - 20t
<h3>Ratio of the distance traveled by the cars</h3>
D₂/D₁ = (70t) / (50t + 100)
Learn more about distance traveled by a vehicle here: brainly.com/question/6504879
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Answer:
1, 11x + 3y + 15z
2, 3x + 12y + -5z
Step-by-step explanation:
all you need to do is combined the like terms and make sure the signs (<em>positive and negative signs</em>) are right
if each block is 2/3 miles long, and he walks 4 1/2 blocks, we can simply multiply to two. It looks like this:
(2/3)(4 1/2)
to multiply, make 4 1/2 into an improper fraction and multiply normally
(2/3)(9/4)
Ton walks 3 miles total.
