1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stellarik [79]
3 years ago
6

(25 points)

Mathematics
2 answers:
kotykmax [81]3 years ago
5 0

Answer:

Just divide it by 2 for your answer

Step-by-step explanation:

297 divided by 2 5o get your answer

Irina18 [472]3 years ago
3 0

Answer:

Take $2975 divided by 2, then take that number divided by $17,500 to figure out the annual interest rate.

Annual interest rate: 8.5%

Step-by-step explanation:


You might be interested in
Help me answer this please and thanks cause I don't see myself getting the answer anytime soon lol
cluponka [151]

Answer:x2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the solution for y=4x−9
nignag [31]
To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept: (9/4,0)

y-intercept: (0,−9)
7 0
4 years ago
1. Ms. Dawson’s call did a science experiment. The class started out with 650 bacteria cells. The growth rate predicted was 4.75
MatroZZZ [7]

The exponential function is y = 650(1.0475)ˣ

<h3>Exponential equation</h3>

A Exponential equation is in the form:

y = abˣ

where y, x are variables, b is the multiplier and a is the initial value.

Let y represent the bacteria population after x hours.

a = 650 bacteria

b = 100% + 4.75% = 1.0475

The exponential function is y = 650(1.0475)ˣ

After 33 hours:

y = 650(1.0475)³³ = 3006

Find out more on Exponential equation at: brainly.com/question/2456547

8 0
2 years ago
What is the mass of a 7.91cm3 piece of lead having a density of 11.34g/cm
Viktor [21]

Answer:

89.6994g

Step-by-step explanation:

M = DV

   = 11.34g/cm^3 * 7.91cm^3

   = 89.6994g

Hope this helps!

8 0
3 years ago
A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

p(50) = 20(1.014)50 = 40.08... 

p(100) = 20(1.014)100 = 80.32... 

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth. 

The rate of change is 0.8. 

7 0
3 years ago
Other questions:
  • In 10 minutes a heart rate can be 700 times at this rate how many to minutes will a heartbeat 140 times at what rate can a heart
    11·1 answer
  • Earn 800 a month. Spend 10% of her monthly budget in clothes and food, how mUchiha does she spend on clothes and food
    12·1 answer
  • A particular sound wave can be graphed using the function
    11·1 answer
  • Oakland has an elevation of 1,639 feet above sea level lake enriquilos elevation is 149 feet below sea level what difference in
    8·1 answer
  • Describe the transformations of the following Absolute Value
    7·1 answer
  • The base of an exponential function is 1.024. is the base a growth decay factor, why or why not
    8·2 answers
  • Which correctly describes the roots of the following cubic equation x^3-5x^2+3x+9=0?
    12·1 answer
  • Can someone explain the steps to this ? :)
    15·1 answer
  • FIND THE LATERAL SURFACE AREA OF THE RECTANGULAR PRISM IN CENTIMETERS?
    6·1 answer
  • Find the slope between the two points.<br> (2,7) and (5, 8 )
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!