The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
<h3>What is vertex of parabola?</h3>
The vertex of parabola is the point at the intersection of parabola and its line of symmetry.
Now the given function is,
f(x) = 2x^2 – x – 6
Also, it is given that the vertex is located at (0.25, -6) and the parabola opens up, the function has two x-intercepts.
Comparing the given function with standard form,
f(x) = a x^2 bx + c
By comprison we get,
a = 2
b = -1
c = -6
Now, x-coordinate of vertex is given as,
x = -b/2a
put the values we get,
x = -(-1)/2*2
or, x = 1/4
Put the value of x in given function, so y-coordinate of the vertex is given as,
f(1/4) = 2(1/4)² - 1/4 - 6
= -49/6
= -6 1/8
Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
More about vertex :
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Sorry but where is the picture? I’m confused..
Answer/Step-by-step explanation:
Ok so there is
3, 0-4 4, 5-9 2, 10-14 1, 15-19 1, 20-24
so you can get rid of the last one saying it has more than 1 number between 20-24.
The 3rd one has to short of numbers for 0-4.
the second one has way to many 0-4's when there should be 3 of them.
therefore your answer is The firstone.
I think it's 20. Sorry if it's wrong
Answer:

=> the greatest integer is 2
the smallest integer is -2