$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9$

6 0

3 years ago

Triangle ABC is transformed to obtain triangle A′B′C′:

Lisa [10]

Answer:

Option C is right.

Step-by-step explanation:

Given is a graph with two triangles marked on it.

Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)

Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)

On comparison we find corresponding side of AB is A'B'

Length of AB = 8 and Length of A'B' = 4.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.

Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin. The degree of rotation is 180 degrees.

Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees

8 0

3 years ago

Are the fractions 2/2 and 8/8 equivalent fractions​

Are the fractions 2/2 and 8/8 equivalent fractions