Please help i don't know the answer to number 11

Mathematics

1 answer:

vivado [14]2 years ago

6 0

The length of midpoint connected size is half of the size of the triangle that it's parallel to. that's means lengh of sizes are half of the original.

area of triangle with known side a, b, c
s = (a+b+c)/2
area = sqrt(s(s-a)(s-b)(s-c))

area of midpoint triangle wih side a/2, b/2, c/2
s' = (a/2+b/2+c/2)/2 = (a+b+c)/4 = s/4
area' = sqrt(s'(s'-a/2)(s'-b/2)(s'-c/2))
= sqrt(s/2(s/2-a/2)(s/2-b/2)(s/2-c/2))
= (1/4)sqrt(s(s-a)(s-b)(s-c)) = (1/4)area

answer is 1/4

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aliya0001 [1]

Answer:

1) 8x

2) 12x - 3y

Step-by-step explanation:

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2 years ago

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Or a very large set of data the measured mean is found to be 288.6 with a standard deviation of 21.2. assuming the data to be no

SashulF [63]

The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.

Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.

So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ

That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)

Answer: 264.22 to 312.98

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3 years ago

50 point available!!!!!!

g100num [7]

Answer:

2 miles is your answer hope this helps!!!!!!

Step-by-step explanation:

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3 years ago