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3 years ago

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Mathematics

2 answers:

posledela3 years ago

4 0

Answer:

Step-by-step explanation:

Rashid [163]3 years ago

3 0

*Hint: When a figure is reflective about the y-axis, the rule would be (-x, y)

So as you can see, all the points of the figure changed from a negative x to a positive one but kept the same y value. And then after the translation up by 6 units, the final rule would be (-x, y + 6) and if you were to plug in the points, you would see they would end up as the image.

The answer to this question would be:

B.) Reflection about the y-axis followed by translation up by 6 units.

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1) a=b+√b²+√c² make c the subject of the formula

Nonamiya [84]

Answer:(A²-B²) = (A-B)² + 2AB

Step-by-step explanation:

5 0

3 years ago

14 over 15 divided by 28

Hoochie [10]

Answer:

1/30

Step-by-step explanation:

When we are dividing fractions, we can turn it into multiplication

14/15 divided by 28

14/15 x 1/28

14/420

simplified to 1/30

8 0

3 years ago

Read 2 more answers

2. List the like terms in each of the following: i) 6a , 13b2 , -2a , 2a2 , -b2 , bc

lana [24]

13b2 &-b2
6a & -2a

i m not sure about the answer ...

3 0

2 years ago

Given: ∆SPM, PK⊥ SM SP = 25, SM = 28, PK = 9 Find: m∠S, m∠M, PM

nevsk [136]

Answer:

∠S = 21.10°

∠M = 79.45°

PM = 9.16

Step-by-step explanation:

Here Pythagorean theorem and trigonometry suffice to solve our problem.

From the Pythagorean theorem we get:

$KM^2+9^2=PM^2$ and

$(25-KM)^2+9^2=25^2.$

We solve for $KM$ in the second equation and get:

$(25-KM)=\sqrt{25^2-9^2}$

$\therefore KM=25-\sqrt{25^2-9^2} =\boxed{1.68}$

Now since

$SK+KM=25\\\\ SK=\boxed{23.32}$

Therefore

${\angle}S=Tan^{-1}(\frac{PK}{SK}) = Tan^{-1}(\frac{9}{23.32})=21.10^o$

and

${\angle}M=Tan^{-1}(\frac{PK}{KM}) = Tan^{-1}(\frac{9}{1.68})=79.45^o.$

And finally again from the Pythagorean theorem:

$PM^2=PK^2+KM^2=9^2+1.68^2$

$\therefore PM=\sqrt{9^2+1.68^2} =9.16.$

Thus,

∠S = 21.10°

∠M = 79.45°

PM = 9.16.

7 0

3 years ago

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

3 0

3 years ago