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3 years ago

Evaluate 9/m+4 when m=3

Mathematics

1 answer:

Nikolay [14]3 years ago

6 0

Answer:

$\frac{9}{7} \: or \: 1.28$

Step-by-step explanation:

$\frac{9}{m + 4} = \frac{9}{3 + 4} = \frac{9}{7} \: or \: 1.28$

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Mandy used the graph to write the equation of the line it represents. She took these steps. 1. y−intercept = (0, 2) 2. Slope = r

Katyanochek1 [597]

Based on the information given about the equation, y will be 0.5x + 2.

<h3>How to illustrate the equation?</h3>

From the information given, it should be noted that the equation of the line it represents was given and the y intercept is = (0, 2).

The function to represent y will be:

y = mx + b

y = (1/2)x + 2

y = 0.5x + 2

In conclusion, y = 0.5x + 2.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

3 0

2 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

4 years ago

Please help me. will mark brainliest. what is the answer?

VARVARA [1.3K]

Answer:

A ) y=-1/2x+2

Step-by-step explanation:

since the equation is y=2x+4 and the points are (-2,3) and the line is perpendicular to that equation

y=-1/2x+b

enter the point (-2,3)

3=1+b

b=2

y=-1/2x+2

3 0

4 years ago

One speed skater starts across a frozen lake at an average speed of 8 m/s. Ten seconds later, a second speed skater starts from

Galina-37 [17]

Answer: Hello mate!

Let's define the variable t as the time, and define t = 0 as the moment when the first skater starts to move:

We know that the speed of the first skater is 8 m/s, and we need to find the position as a function of time, then we need to integrate the velocity over time

if v1(t) = 8m/s

then p1(t) = (8m/s)*t

now we also know that the second skater has a velocity of 9m/s and enters in the frozen lake at t= 10s.

then the velocity of the second skater is: v2(t) = 9m/s, and the position is:

p2(t) = (9m/s)*(t - 10s)

now we want to know how many seconds after the second skater starts are needed for the second skater to overtake the first one.

this is equivalent to see when his positions will be equal.

so p1(t) = p2(t):

(8m/s)*t = (9m/s)(t - 10s) = (9m/s)*t - 90m

(8m/s)*t - (9m/s)*t = -90m

(-1m/s)*t = 90m

t = 90m/(1m/s) = 90s

Then in t = 90 seconds, the second skater will overtake the first one, and knowing that the second skater started at t = 10 seconds; there are 80 seconds after the second skater started needed to overtake the first skater.

7 0

3 years ago

for every 5 red cars there are 8 black cars. If there are 24 more black cars than red cars how many total vehicles are there

NARA [144]

Answer:

15 red cars + 24 black cars = 38

6 0

3 years ago

Read 2 more answers