so we have a 33, namely two real solutions for that quadratic.
usually that number goes into a √, if you have covered the quadratic formula, you'd see it there, namely that'd be equivalent to √(33), now 33 is a prime number, and √(33) is yields an irrational value, specifically because a prime number is indivisible other than by itself or 1.
so 33 can only afford us two real irrational roots.
Answer:
22
Step-by-step explanation:
QS =2×11 = 22
__________
Answer:
D) a hyperbola
Step-by-step explanation:
IMO, the image is not helpful, as it suggests the ends of the curve are nearly parallel to each other. In fact, the ends of the curve asymptotically approach straight lines parallel to the sides of the cone. That is, there are asymptotes that form an X shape. This is a characteristic of a hyperbola.
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A parabola is formed when the plane cuts the cone parallel to one side. That cut plane only intersects one nap of the cone. At a shallower angle yet, one gets an ellipse. Parallel to a base, one gets a circle.
Answer:
2.25c + 1.75p ≤ 28
1.25c + 2.125p ≤ 30
Step-by-step explanation:
Write a system of two inequalities to model loaves of bread and
cake that can be baked.
let
number of cornbread loaves = c
number of poppy-seed blueberry Cake loaves = p
corn bread
cups of flour = 2 1/4 = 2.25
teaspoon of baking soda = 1 1/4 = 1.25
One loaf of poppy-seed blueberry cake
cups of flour = 1 3/4 = 1.75
teaspoons of baking soda = 2 1/8 = 2.125
The bakery has 28 cups of flour and 30 teaspoons of baking soda in stock.
Quantity of flour to use
c(2.25) + p(1.75)
Quantity of baking soda to use
c(1.25) + p(2.125)
The inequality is
c(2.25) + p(1.75) ≤ 28
c(1.25) + p(2.125) ≤ 30
Alternatively,
2.25c + 1.75p ≤ 28
1.25c + 2.125p ≤ 30
Answer:
The food store used 3 lbs of clusters, 6 lbs of granola, and 3 lbs of raisins.
Step-by-step explanation:
Given that:
A food store makes a 12-lb mixture of granola, clusters, and raisins.
The cost of granola = 1.00 per pound
The cost of clusters = 3.00 per pound
The cost of raisins = 2.00 per pound
Let granola be = g; cluster be c and raisins be r
Then, g + c + r = 12
Similarly, the mixture calls for twice as much granola as clusters.
2c + c + r = 12
3c + r = 12
r = 12 - 3c
2c(1) + 3c + 2r = 21
2c + 3c + 2r = 21
5c + 2r = 21
5c + 2(12 -3c) = 21
5c + 24 - 6c = 21
24 - c = 21
-c = 21 - 24
c = 3
Thus, cluster c = 3 lbs
granola = 2(c) = 2(3) = 6 lbs
raisins = 12 - 3c
= 12 - 3(3)
= 12 - 9
raisins = 3 lbs
