The zeros of this function is when y = 0.
(x, 0) and (x,0)
Looking on the graph
It would be (3,0) and (6,0)
The solution is x = 3, x = 6
<u />how many times does 6 go in 12 it is 2
Answer:
A. m^2+7m+10=0
Step-by-step explanation:
This is a problem in pattern matching, and in substituting a variable for a pattern.
(x^2+3)^2 +7x^2 +21 = -10 . . . . . . given
(x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms
m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3
m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A
I think it would be 137.1, due to the total being 360. Just subtract.