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Orlov [11]
3 years ago
15

Help please! I kind of forgot how to do these & I need a little bit of help, thank you!

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

T

Step-by-step explanation:

Go to the right 1/4 of a unit and down 1/2 of a unit

The point is T

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5q - p + p + 1, please help!
Mamont248 [21]
So basically you just add the like terms to simplify the equation. You have 5q-p+p+1 you can cancel out the both p’s because one is negative and one is positive. That leaves you with 5q + 1 they are not like terms so you cannot simplify them so your simplified equation is 5q +1
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2 years ago
Which fraction is equivalent to 6/8. A.8/9. B.4/6. C.9/12. D.8/10
DaniilM [7]

<u>Answer</u><u>:</u>

<h2>C. 9/12</h2>

<u>Explanation:</u>

<em>6</em><em>/</em><em>8</em><em> </em><em>simplifies </em><em>to </em><em>3</em><em>/</em><em>4</em>

<em>3</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>9</em>

<em>4</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em>

<em>Since </em><em>they </em><em>are </em><em>both </em><em>multiples </em><em>of </em><em>3</em><em>,</em><em> </em><em>it's </em><em>e</em><em>quivalent</em><em> </em><em>to </em><em>6</em><em>/</em><em>8</em><em>.</em>

7 0
2 years ago
How do I find the restrictions on x if there are any? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%20-%201%7D%20%20%3
Natali5045456 [20]

We have the expression:

\frac{1}{x - 1}=\frac{5}{x - 10}

When we have rational functions, where the denominator is a function of x, we have a restriction for the domain for any value of x that makes the denominator equal to 0.

That is because if the denominator is 0, then we have a function f(x) that is a division by zero and is undefined.

If we have a value that makes f(x) to be undefined, then this value of x does not belong to the domain of f(x).

Expression:

\begin{gathered} \frac{1}{x-1}=\frac{5}{x-10} \\ \frac{x-1}{1}=\frac{x-10}{5} \\ x-1=\frac{x}{5}-\frac{10}{5} \\ x-1=\frac{1}{5}x-2 \\ x-\frac{1}{5}x=-2+1 \\ \frac{4}{5}x=-1 \\ x=-1\cdot\frac{5}{4} \\ x=-\frac{5}{4} \end{gathered}

Answer: There is no restriction for x in the expression.

6 0
11 months ago
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