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serg [7]
3 years ago
5

20r3 − 16r2 + 15r − 12

Mathematics
1 answer:
kati45 [8]3 years ago
7 0

Answer:

(5r-4)(4r^(2)+3)

Step-by-step explanation:

Hope it helps

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-7a + 5a = -25 + 21 Solve for a<br><br> If you can't figure it out its ok!
Sladkaya [172]

Answer: a = 2

Step-by-step explanation: combine both sides. Remove variable by dividing, answer is 2

7 0
2 years ago
Read 2 more answers
Solve the simultaneous equations:<br> 3x + 2y = 35 <br> 2x + 3y = 30
lesya [120]

Answer:

nuber 1

Simplifying

3x + 2y = 35

Solving

3x + 2y = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

3x + 2y + -2y = 35 + -2y

Combine like terms: 2y + -2y = 0

3x + 0 = 35 + -2y

3x = 35 + -2y

Divide each side by '3'.

x = 11.66666667 + -0.6666666667y

Simplifying

x = 11.66666667 + -0.6666666667y

5 0
3 years ago
If the cost of 9 m cloth is rupees 378, find the cost of 4 m cloth? guys little fast and please in steps no direct answers
yulyashka [42]

Answer: 168 rupees.

Step-by-step explanation:

sure thing! first, i divided 378 by 9, so that i could find the cost of ONE meter of cloth.

378/9 = 42

then, i just multiplied 42 by 4, in order to find the total cost for 4 meters.

42 x 4 = 168

3 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
- Brainliest- friend me.A spinner is divided into four equal sections. Which situation can be represented using this simulation?
Verdich [7]

Answer:

im pretty sure its 2 answers

both a and c

hope this helps!!

5 0
3 years ago
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