I will send you a hopefully helpful link. https://www.ncdc.noaa.gov/sotc/national/201403
The relationship between space, time and velocity for a uniform motion is given by:

where
S is the distance covered
t is the time
v is the velocity
The plane in our problem has a velocity of

and so during a total time of t=4 h, the distance it covers is

therefore, 680 miles.
I found this for you. It even tells you how the answer was achieved.
From the problem we have
In △ABC, m∠A=52°, c=11, and m∠B=19°.
Draw the diagram with the help of given information, (see the attached image)
Now using Sine Law in the Triangle ABC, we can write
Now from Triangle ABC , we can write


Now simplify , we get

Rewrite as improper fractions 3 2/3 is (3*3+2)/3=11/3 and 14 2/5 is (5*14+2)/5=72/5 product means multiply so multiply the numerators and then denominators Numerators 11*72=792
denominators 3*5= 15 so then the answer is 792/15 = 52 12/15 =52 4/5