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GREYUIT [131]
3 years ago
13

Currently, there are 420 cars in the parking lot. Campus security needs the set up for an event. They have only ten minutes to m

ake sure that the parking lot has only 50 cars. Write an equation that would allow them to calculate x, the number of cars to leave the parking lot each minute.
Mathematics
1 answer:
Nady [450]3 years ago
8 0

Answer:

The number of cars to leave parking lot each min = 37

Step-by-step explanation:

Numbers of cars in parking lot = 420

Time required to make sure that parking lot have only 50 cars = 10 minutes

So ,number of cars to leave parking lot = 420 - 50 = 370

∵  10 min required to leave number of cars = 370

∴ For 1 min , number of cars to leave  = \frac{370}{10} = 37

Hence The number of cars to leave parking lot each min = 37    Answer

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What is the solution to the following equation?
nexus9112 [7]

Answer:

The answer to your question is the letter B. x = 6

Step-by-step explanation:

Data

               4x² - 48x = -144

Process

1.- Equal to zero

               4x² - 48x + 144 = 0

2.- Multiply 4 by 144

             4 x 144 = 576

3.- Find the prime factors of 576

                     576   2

                     288   2

                     144    2

                       72    2

                       36   2

                       18    2

                        9    3

                        3     3

                         1

4.- Find two numbers that added gives -48,

     these numbers are -24 and -24

5.- Write the equation using these numbers

              4x² -24x - 24x + 144 = 0

6.- Factor by grouping

             4x(x - 6) - 24(x - 6)

7.- Factor by like terms

             (x - 6)(4x - 24)

8.- Find the solutions

              x - 6 = 0           4x - 24 = 0                            

              x = 6                   4x = 24

                                        x = 24/4

                                        x = 6

8 0
3 years ago
Bill Ding plans to build a new hardware store. He buys a rectangular lot that is 50 ft by 200 ft, the 50-ft dimension being alon
enot [183]

Answer:

Length a = 59.62

Width b = 67.09

Cost = $10,734.4

Step-by-step explanation:

Solution:

Let a be the length and b be the width.

Area of the rectangle = a x b

a x b = 4000

Cost of the construction:

Cost = 100a + 80(a + 2b)

Cost = 100a + 80a + 160b

Cost = 180a + 160b     Equation of the Cost of the construction.

Now, we need a and b to calculate the minimum cost required to build a lot.

From the area = a x b

we have,

a x b = 4000

b = 4000/a

Putting this equation into the cost of the construction.

We get:

Cost = 180a + 160 x (4000/a)

Cost = 180a + 640000/a

Differentiating with respect to a, we get

C^{'} = 180 - 640000/a^{2}

Putting C^{'} = 0

180 - 640000/a^{2} = 0

Taking LCM

180a^{2} - 640000 = 0

Solving for a

180a^{2} = 640000

a^{2} = 640000/180

a^{2} = 3555.55

Taking square root

a = 59.62

As we know,

b = 4000/a

putting the minimum value of a  = 59.62

b = 4000/59.62

b = 67.09

So, now we have both the dimensions a and b

Putting the values of a and b we will get the cost of the construction.

Cost = 180a + 160b

Cost = 180(59.62) + 160(67.09)

Cost = $10,734.4

Hence, $10,734.4 will be the minimum cost of the construction for Bill Ding.    

5 0
3 years ago
What is the degree of angle e and g
Zina [86]

Answer:

e=g = 126 degree

Step-by-step explanation:

e = g (opposite angles's property)

g+ b = 180 ( supplementary angles's property)

b = 54 degree (opposite angles's property)

-> g = 180-54 = 126

-> e = 126 degree

3 0
3 years ago
Read 2 more answers
9 3/4% comverted to a fraction
daser333 [38]
The answer should be 39/400
5 0
3 years ago
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What is cos(npi/2) and sin(npi/2) in fourier series cos(npi) is (-1)^n and sin(npi)=0 ?
Nat2105 [25]
The problem ask to fourier series of the trigonometric function base on the data you have been given in the problem, so the answer would be cos(pi/2n) = {(-1)^n/2 - if n is even, 0 - if n is odd} and sin(pi/2n) = {0- if n is even, (-1)^(n-1)/2 if n is odd}. I hope you are satisfied with my answer 
4 0
3 years ago
Read 2 more answers
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