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Virty [35]
3 years ago
11

Please help me solve this, Thank you.

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

Expression equivalent to 4x + \frac{1}{2}  + 2x - 3  = 6x -(\frac{5}{2})

Step-by-step explanation:

Here, the given expression is :4x + \frac{1}{2}  + 2x - 3.

Now, simplifying the given expression by adding Like terms with Like terms, we get:

4x + \frac{1}{2}  + 2x - 3  = (4x + 2x) + (\frac{1}{2}  -3)\\=( 6x)  + \frac{1 - 3(2)}{2}  = 6x + (\frac{1-6}{2}) \\=6x -\frac{5}{2} \\\implies 4x + \frac{1}{2}  + 2x - 3  = 6x -(\frac{5}{2})

Hence an expression equivalent to 4x + \frac{1}{2}  + 2x - 3  = 6x -(\frac{5}{2})

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Out of 24 problems total she completed the first 12 problems in 1 hour and the last 12 problems in 3 hours what is the unit rate
finlep [7]

Answer:

6

Step-by-step explanation:

your answer is 6 because she did 12 in 1hr and the other 12 in 3hr so you take 3=1+4 and divide 24 by 4 which is 6

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Name this line in 3 ways
faltersainse [42]

Straight

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What is the sum of the rational expressions below?
Anna71 [15]

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Step-by-step explanation:

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4 years ago
X +11 -8 ÷ -2<br><br>I need help, it's a to step-equation!! ​
____ [38]

Answer:

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Step-by-step explanation:

x+11-8/-2

first do -8/-2=4

so it is x+11+4

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6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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