The 3rd option is exponential decay
Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks
Answer: a is the # of elements in A but NOT B, that is A ONLY
b is the # of elements in B but NOT A, that is B only
N is the # of elements in the INTERSECTION of A and B
a + N = 99
b + N = 25
a + b + N = 123
Subtracting the first two equations: a - b = 74
Subtracting the last two equations: -a = -98
a = 98
So then a - b = 74 and a = 98
98 - b = 74
-b = -24
b = 24
a = 98, b = 24 and a + b + N = 123
98 + 24 + N = 123
122 + N = 123
N = 1
98 are in A only
24 are in B only , which is the answer to the question
1 is in both A and B
Step-by-step explanation:
<span>We have the sequence that follows the pattern: a n = - 4 n + 13. If we want to calcelate the 14th term in this sequence ( or a 14 ), we have to substitute in this formula: n = 14. Then we will get: a 14 = - 4 * 14 + 13 a 14 = - 56 + 13, and finally: a 14 = - 43. Answer: The 14th term in the sequence is - 43.</span>
