Given :
A point U located at (1,-4) on the coordinate plane.
To Find :
The reflection of point U on x-axis.
Solution :
Reflection of any point ( h , k ) on x-axis is ( h , - k ) .
So , the reflection of point U i.e ( 1 , -4 ) is ( 1 , 4 ) .
Therefore , the ordered pair describes the location of U' is ( 1 , 4 ).
Hence , this is the required solution .
For the proof here kindly check the attachment.
We are given that
. Also, the transversal is shown. Let us take the first case, that of 
and 
. Please note that all other proofs will follow in a similar manner.
Let us begin, please have a nice look at the diagram. We will see that and 
are vertically opposite angles. We know that vertically opposite angles are congruent. Thus, and are congruent angles.
=
Now, we know that and are alternate interior angles. We also, know that alternate interior angles are equal too. Thus, we have:
=
From the above arguments it is clear that:
= = .
Thus, =
We have proven the first instance. Please note that all other instances can be proved in a similar fashion.
For example, for 
and 
we can take and 
as vertically opposite angles thus making = . Now, and are alternate interior angles and thus and are equal. Thus, we have and .
Answer:
I aint never seen two pretty best friends, its always one of em gotta be ugly
Step-by-step explanation:
Answer:
(6,6)
Step-by-step explanation:
3x+5y=48
-3x+5y=12
Ok so when you're doing elimination you want to combine all of the like terms. In this case, we need to combine 3x and -3x, 5y and 5y, and 48 and 12. 3x and -3x cancel out, so that leaves you with 10y=60. Solving for y gives you y=6. Now you need to solve for x, so using 3x+5y=48, by plugging in y you get 3x+(5*6)=48. Simplifying that gives you 3x+30=48. Subtract 30 and divide by 3, and you get x=6. Thus the Answer is (x,y) or (6,6)
Answer: jdkdkkdmdmmmddm
Step-by-step explanation:
