There is no real planet that is 1/10 the distance Uranus is from the sun, however the planetoid (smaller planet), Vesta is 1/9 the distance Uranus is from the sun.
Answer:
- 12 ft parallel to the river
- 6 ft perpendicular to the river
Step-by-step explanation:
The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.
72 = W(2W)
36 = W²
6 = W . . . . . . the width perpendicular to the river
12 = 2W . . . . the length parallel to the river
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<em>Development of this relation</em>
Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...
A = xy = x(T -x)/2
Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...
x = (0 +T)/2 = T/2
The corresponding area width (y) is ...
y = (T -T/2)/2 = T/4
Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.
Answer:
The solution is (3/8, -7/8).
Step-by-step explanation:
y = −5x + 1
y = 3x − 2
Since the 2 expressions in x are both equal to y :
−5x + 1 = 3x - 2
-5x - 3x = -2 - 1
-8x = -3
x = 3/8.
So y = 3x - 2
= 3(3/8) - 2
= 9/8 - 2 = -7/8.
Answer: False
Step-by-step explanation:
You didn't give the coordinate plane that I was supposed to use while helping you.
