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garri49 [273]
3 years ago
10

Explain how you would solve 16/c=8. Then solve the equation

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0
16/c=8
16/c=8/1
cross multiple
16=8c
c=16/8
c=2
Dimas [21]3 years ago
4 0
16/c =8

That means 16 divided by same random number "c" makes the number 8. This also means that 8 times that random number you divided by makes 16.

Using this, you can rearrange the equation in various ways.

16/c =8

16 = c*8

c = 16/8

We only really need that last one, c = 16/8, 

16/8 = 2

c = 2
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Step-by-step explanation:

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Consider the sequence following a minus 8 pattern: 9, 1, −7, −15, ….
photoshop1234 [79]

Answer: -287

Step-by-step explanation:

The given pattern: 9, 1, -7, -15, ….

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a_n=a+(n-1)d

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a_{38}=9+(-8)(38-1)\\\\=9-8(37)=9-296=-287

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3 0
4 years ago
Midpoint between 8.5 and 8.6
iren [92.7K]
8.5+8.6=73.1÷2=36.55
formula for midpont a+b divide 2
                               
7 0
4 years ago
a triangle has a base of 15 inches and an area of 82.5 square inches. What is the height of the triangle
horrorfan [7]

Area of a triangle = 1/2 x base x height.

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8 0
3 years ago
Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d)​, one of which is co
arlik [135]
A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

P(C) = \frac{1}{4}

The probability of choosing wrong answer is

P(W) = \frac{3}{4}

Using the multiplication rule
P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

WWC

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

WCW

Or the first one is correct and the last two are wrong. This will give the arrangement,

CWW
.

P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}

P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64}  \\ \\ P(One \: Correct) = \frac{27}{64}
7 0
4 years ago
Read 2 more answers
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