The equation of line parallel to
and containing the point(-10,-3) is 
Step-by-step explanation:
We need to write the equation parallel to and containing the point(-10,-3)
The standard form of point slope equation is:
where m is slope and b is y-intercept
Comparing the given equation with standard form the slope is m= -1/5
Since the lines are parallel the slope of new line is m = -1/5
Now finding b (y-intercept)
Using slope m=-1/5 and point (-10,-3)
So, b= -5 and slope = -1/5 the equation of new line is:
So, The equation of line parallel to and containing the point(-10,-3) is
Keywords: Point Slope form
Learn more about point slope form at:
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The measures of the legs of the right triangle are:
X = 2.5
Y = 4.3
<h3>
How to find the values of x and y?</h3>
In the image, we can see a right triangle with a hypotenuse with a value of 5, and a known angle.
To find the values of X and Y (the legs of the triangle) we can use the two relations:
Sin(a) = (opposite cathetus)/(hypotenuse)
Cos(a) = (adjacent cathetus)/(hypotenuse)
In this case, we have:
a = 30°
hypotenuse = 5
opposite cathetus = X
adjacent cathetus = Y.
Replacing that in the relations we get:
Sin(30°) = X/5
Sin(30°)*5 = X = 2.5
cos(30°) = Y/5
cos(30°)*5 = Y = 4.3
Learn more about right triangles:
brainly.com/question/2217700
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Answer:
acute-angled
Step-by-step explanation:
It doesn't have a right angle and one of its corners isn't for than 90 degrees
Volume = length * width * height (V = lwh)
