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leonid [27]
3 years ago
14

Please answer ASAP. Thank you! :)

Mathematics
1 answer:
laila [671]3 years ago
7 0
You will have to find what x is to get your answer solve each to find the answer
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Help please!!!<br> Can someone explain how to solve this please?
Greeley [361]

Answer:

12 the answer

Step-by-step explanation:

3 0
3 years ago
Y=1/4x + 8 what would be the slope and the y-intercept
boyakko [2]

slope intercept form is: y = mx + b

m = slope

b = y-intercept

In the equation y = 1/4x + 8

m = 1/4 = slope

b = 8 = y-intercept

6 0
4 years ago
Read 2 more answers
-2/3*3/5+5/2-3/5*1/6​
Kipish [7]

Answer:

2and19/90

Step-by-step explanation:

-2/3*3/5= _2/5

-2/5+5/2-(2/3×1/6)

-2/5+5/2-1/9

21/10-1/9

=199/90

=2/19/90

3 0
4 years ago
Mark -5/7, 2/7, 6/7, -1 on a number line.<br>if u will answer i will mark u as brainlist.​
DerKrebs [107]

Answer:

So first converthem into a deciaml if the number line is ordered by decimals or make them from least to greatest, left to right.

Decimal:

If asking for s decimal, the -1 is definitely the least so -1. For -5/7, it’s just -0.71 (rounded), for 2/7, its 0.28 and for 6/7 its 0.86.

6 0
3 years ago
The water in a river moves south at 10 mi/hr. A motorboat travels due east at a speed of 20 mi/hr relative to the shore. Determi
weeeeeb [17]

Answer:22.36 mi/hr

Step-by-step explanation:

Given

water in a river moves south at (V_w)10 mi/hr

motorboat travels due to east at a speed of (V_b)20 mi/hr

Velocity of boat relative to the moving water V_{bw}

V_{bw}=V_b-V_w

V_{bw}=20i-(-10j)=20i+10j

Magnitude of V_{bw}=\sqrt{20^2+10^2}=\sqrt{500}

V_{bw}=10\sqrt{5} \approx 22.36 mi/hr

tan\theta =\frac{10}{20}

\theta =26.56^{\circ} with the x axis.

4 0
3 years ago
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