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Leokris [45]
3 years ago
12

2^(-3x)=6^(x+4) Solve for x

Mathematics
2 answers:
satela [25.4K]3 years ago
7 0

2^- 3x = 6^x + 4

Solution: x = - 4ln(6)/ln(48) Decimal: (- 1.85137.....)

Solve For X: Step by Step:

2^(- 3x) = 6^(x + 4)

Solve Exponent:

2^-3 = 6^x + 4

log (2^-3x) = log (6^x + 4) (Take log of both sides):

( - 3x) * (log (2)) = (x + 4) * (log (6))

- 3x = (log (6)/(log (2) * (x + 4)

- 3x = 2.584963 * (x + 4)

- 3x = 2.584963x + 10.339852

Simplify both sides of the Equation:

- 3x - 2.584963x = 2.584963x + 10.339852 - 2.584963x

Subtract: 2.584963x From both sides:

- 5.584963x = 10.339852

- 5.584963x = 10.339852

- 5.584963 =====> - 5.584963

Divide both sides by: ===> - 5.584963

Hence: x ===> - 1.851373

Answer: x = - 1.851373

Hope that helps!!!!! : )

gladu [14]3 years ago
6 0

The answer is x = - 140/39. simplify both sides then isolate the variable

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Can someone help me on this
Sidana [21]

Answer:

Area = 702.9 or 703

Step-by-step explanation:

By Pythagoras the. first, we need to find the base!

(H)2 = (P)2 + (B)2

(82)2 = (18)2 + b2

6724 = 324 + b2

b2 = 6724-324

b2 = 6100

b = √6100

b = 78.1

note - they all are in square

Now, area of the triangle:-

1/2 * b * h

1/2 * 78.1 * 18

= 702.9

Hope it helps!

6 0
3 years ago
Read 2 more answers
the length of a rectangle is 5 centimenters less than twice its width. the perimeter of the rectangle is 26 cm. what are the dem
inysia [295]
L = w - 5
2*l + 2*w = 26
2*(w - 5) + 2*w = 26
2w - 10 + 2w = 26
4w = 36
w = 9
l = w - 5
l = 9 - 5
l = 4

Final Answer:
The rectangle is 4cm long and 9cm wide.
Hope I helped :)
4 0
3 years ago
What is the value of x?
Anestetic [448]

They are congruent triangles,

Ratio of their corresponding sides is 5:25, =1:5 (look for hypotenuse)

so, 5x = 18-x   (same manner for variable one)

  18 = 6x

   x=3

SO, OPTION C IS THE ANSWER.

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prisoha [69]
The solution is 12. The problem tells you that when is between 9-13. Then 12 is the answer
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1.6 lbs. = __ gal<br> how many gallons are in 1.6lbs?
Simora [160]
11.9 gallons I think
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