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4 years ago

8

A RAID can fail if two or more of its drives crash within a short time interval. Suppose that the probability of one drive crash

ing in a given hour is p. What is the probability of a k-drive RAID failing in a given hour?

1 answer:

gayaneshka [121]4 years ago

7 0

Answer:

Step-by-step explanation:

ghgh

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Carmen wins $35 was in the contest. Tubes of her favorite brand of paint cost $4.80 each. Paint brushes cost $6.70 each. How man

Zanzabum

6.70 for paint brushes. for 2 is 6.70×2=$13.40

35-13.40=$21.60 left after 2 paint brushes

4.80×4=$19.20 for 4 tubes of paint

21.60-19.20=$2.40 left after 4 tubes of paint and 2 paint brushes

6 0

3 years ago

Simplify 6 x 10−7 2 x 105 .

mafiozo [28]

Answer:

-49

Step-by-step explanation:

it would be this because first we would have to figure out what 6*10 is that why we know what to distribute . so once we figure it out , which is 70 . We would then subtract 14 from 70 . Since 7 is right next to 2 we would then multiply it to get to 14. Once we get that you should get 56, from there you would subtract 56 to 105 , and get your answer.

7 0

3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

<u>Finding P(A)</u>

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

<u>Finding P(B)</u>

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

<u>Finding $P(A \cap B)$ </u>

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago

48 ounces to 5 Pounds (ratio)

koban [17]

Answer:

3:5

Step-by-step explanation:

16 ounces = 1 pound

80 ounces =5 pounds

Simplify:

48:80

6:10

3:5

Hope this helped! :)

4 0

3 years ago

9(14-5)-42 evaluate expression

Ulleksa [173]

Good evening

Answer:

<h2>39</h2><h2 />

Step-by-step explanation:

9(14-5)-42 = 9×9 - 42

= 81 - 42

= 39

________________

:)

8 0

3 years ago