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iris [78.8K]
3 years ago
8

A RAID can fail if two or more of its drives crash within a short time interval. Suppose that the probability of one drive crash

ing in a given hour is p. What is the probability of a k-drive RAID failing in a given hour?
Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

Step-by-step explanation:

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Please help with this
BabaBlast [244]
Slope: (y2-y1)/(x2-x1) = m
Find the slope, m, then pick a point, plug in the x, y, and m, and solve for b in the equation:
y = mx + b
That is your y-intercept.
Take out your x and y, plug in m and b, and that is your generic form for your line, t.
3 0
3 years ago
3x+y=23, 6x-y=50, what is the value of x and y
Mice21 [21]

Answer:

3x+y=23

6x-y=50

2(3x+y)=2(23)

6x+2y=46

(6x-y)-(6x+2y)=50-46

-3y=4

y=-4÷3

=-4/3

x=[23-(-4/3)]÷3

=24/1/3÷3

=73/3÷3

=73/9

4 0
2 years ago
Given ΔRWS ≅ ΔTUV, find the values of x and y. <br><br> x = ___<br><br> y = ___
Oksanka [162]

Answer: A = X + Y

B = X or Y. A = 12, B = 8, X = 2, Y = 10, A = 12, B = 9.

Step-by-step explanation:

3 0
3 years ago
The shadows of two vertical poles were measured at the same time to be 6m and 15m long. If the first pole is 8cm long, find the
son4ous [18]

Answer:

20 cm

Step-by-step explanation:

Shadow of vertical poles : 6m ; 15m

Length of poles : 8cm ; h

8cm long pole = shadow length, 6m

h cm long pole = shadow length, 15 m

Using cross multiplication :

8cm * 15 m = h cm * 6m

120 = 6h

h = 120 / 6

h = 20 cm

Height of second pole = 20cm

8 0
3 years ago
The number of members on an organization increases by an average of 125 members annually. There were 3,875 members in 1971. Choo
Lena [83]

Answer:

B.

Mn = Mn-1 + 125 for n > 1 ; M1 = 3,875

Step-by-step explanation:

Since they tell us after 1970, the first data would be that of 1971 and also that if we started since 1970, we do not know the data of 1969, therefore answer B is correct.

Replacing:

Let M1 = 1971 then Mn-1, that is M0 = 1970, we know that the population of 1970 the population is 3750, because it would be 125 less than the subsequent year, and in 1975 there are 3875. Therefore:

in n = 1

 M1 = M0 + 125

3875 = 3750 + 125

this gives an equality, thus fulfilling the equation.

8 0
3 years ago
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