The second projectile was travelling 1.4 times faster than the first. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

4 0

3 years ago

An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha

hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

$Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}$

Cross multiply

|AB|X Tan 15 =3000

|AB| = $\frac{3000}{Tan 15}$ =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0

3 years ago