1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergeeva-Olga [200]
3 years ago
9

The shadows of two vertical poles were measured at the same time to be 6m and 15m long. If the first pole is 8cm long, find the

height of the second pole
Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

20 cm

Step-by-step explanation:

Shadow of vertical poles : 6m ; 15m

Length of poles : 8cm ; h

8cm long pole = shadow length, 6m

h cm long pole = shadow length, 15 m

Using cross multiplication :

8cm * 15 m = h cm * 6m

120 = 6h

h = 120 / 6

h = 20 cm

Height of second pole = 20cm

You might be interested in
Nine cards are numbered from 1 to 9 and placed in a box. One card is selected at random and not replaced. Another card is random
gizmo_the_mogwai [7]

Answer:

1/6

Step-by-step explanation:

There are 4 primes. So the probability for the first draw is 4/9. Since the card is not replaced, the second probability is 3/8. 3/8 * 4/9 is 12/72, which simplifies into 1/6.

8 0
3 years ago
Read 2 more answers
Find the slope <br> help with this please it’s due soon :)
GrogVix [38]
Undefined!! i hope this helps
4 0
3 years ago
Which is a better deal for a package of soap?
Fittoniya [83]
The best deal for a package of soap would be (a).
5 0
4 years ago
Read 2 more answers
Suppose that we have the following sequence :
Jlenok [28]
a_n=\dfrac12a_{n-1}
a_n=\dfrac1{2^2}a_{n-2}
a_n=\dfrac1{2^3}a_{n-3}
a_n=\cdots=\dfrac1{2^{n-1}}a_1
a_n=\dfrac1{2^{n-1}}

b_n=b_{n-1}+\dfrac1{2^{n-1}}
b_n=b_{n-2}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}
b_n=b_{n-3}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\dfrac1{2^{n-3}}
b_n=\cdots=b_1+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\cdots+\dfrac12
b_n=a_1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}
b_n=1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}
b_n=\displaystyle\sum_{k=1}^n\frac1{2^{n-k}}
b_n=\displaystyle\frac1{2^n}\underbrace{\sum_{k=1}^n2^k}_{S_n}

S_n=1+2+2^2+\cdots+2^{n-1}+2^n
\implies2S_n=2+2^2+2^3+\cdots+2^n+2^{n+1}
\implies S_n-2S_n=-S_n=1-2^{n+1}
\implies S_n=2^{n+1}-1

b_n=\dfrac{2^{n+1}-1}{2^n}=2-\dfrac1{2^n}

\implies b_{50}=2-\dfrac1{2^{50}}\approx1.99999999999999911182158

\implies b_{10^6}=2-\dfrac1{2^{10^6}}\approx2.00000000000000000000000
8 0
3 years ago
Angles a and b are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of b
Andrews [41]
The value of b is 5 by combining like terms.
7 0
4 years ago
Read 2 more answers
Other questions:
  • The Rodriguez family dined at a restaurant. Their bill came to $119, but they also have to pay a 9% tax and they plan to leave a
    12·2 answers
  • You play a video game for 15 minutes. You lose 75 points. What integer represents the mean change in points per minute?
    7·1 answer
  • On my brother's 14th birthday, he was 160 cm tall. Within exactly one year, his height increased by 6%. How tall was he on his 1
    9·1 answer
  • Can someone please help
    12·1 answer
  • At a local school, 940 students each wrote 40 letters in students in another country. How many letters were written in all?
    9·1 answer
  • 3:45 in 24 hour clock
    13·1 answer
  • What is the square root of -1?
    13·1 answer
  • Hey! i’ll give brainliest please help
    11·1 answer
  • 54,392 rounded to the hundreds place
    14·1 answer
  • QUICK! I NEED HELP!!
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!