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Tom [10]
3 years ago
10

Bonnie deposits $70.00 into a new savings account. The account earns 4.5% simple interest per year. No money is added or removed

form the savings account for 3 years. What is the total amount of money in her savings account at the end of the 3 years
Mathematics
2 answers:
Vikentia [17]3 years ago
7 0
The total amount of money would be $79.45 because if you do the equation:
interest=simple interest x time x principal(amount you originally put in) you will get a total interest of $9.45. if you want the total that is in your account, you will need to add the total amount of interest to your principal amount or the amount you first put in which is 70.
never [62]3 years ago
5 0

Answer:

The amount in the account would be 79.45

Step-by-step explanation:

To determine the amount that will be in the account, we can use the simple interest equation.

A = P + Prt

A = 70 + 70(.045)(3)

A = 70 + 9.45

A = 79.45

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If you distribute 4 to 14.99 then you get the answer above. 
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Jonna needs to travel 496 miles in 8 hours. How fast does she need to go in order to reach her destination on time?
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3 years ago
How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
  7. {c}
  8. { } ..... the empty set

Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

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