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irina [24]
3 years ago
9

Aki's Bicycle Designs has determined that when x hundred bicycles are​ built, the average cost per bicycle is given by​ C(x)equa

ls0.2xsquaredminus0.4xplus6.636​, where​ C(x) is in hundreds of dollars. How many bicycles should the shop build to minimize the average cost per​ bicycle?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

100 bicycles

Step-by-step explanation:

If C(x)= 0.2x²-0.4x+6.636

The general form of a quadratic expression is given as: ax²+bx+c

Therefore from C(x),

a=0.2, b=-0.4, c=6.636.

C(x) is a parabola with its "a" coefficient 0.2 being positive so the curve opens upward indicating that the vertex is a minimum.

We simply need to find the vertex of:

C(x)= 0.2x²-0.4x+6.636

This occurs when:

x = -b/(2a)

x = -(-0.4)/(2*0.2)

x = (0.4)/(0.4)

x = 1

Since x=1 at the vertex, the company should build 100 bicycles to minimize the average cost per bicycle.

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Answer:

45 cm

Step-by-step explanation:

l=\sqrt{r^2+h^2}=\sqrt{27^2+36^2} =45 cm

7 0
3 years ago
Paulina works out with a 2.5 kilogram mass. What is the mass of the 2.5 kilogram mass in grams?
Liono4ka [1.6K]
2.5 kilograms in grams is 2500 grams.

2.5kg = 2500g
5 0
4 years ago
Matt's phone bill consist of an initial monthly charge of $30 and then he pays $4.50 per gigabyte of internet he uses. If he spe
ivanzaharov [21]

Answer:

5 gigabytes

Step-by-step explanation:

30+4.50x=52.50 (equation)

-30           -30

4.50x=52.50

/4.50   /4.50

x= 5

5 gigabytes

5 0
4 years ago
It takes Bruce 12 h to complete his training. It takes Oliver approximately 2 days, 2 h, and 15 min to complete
Stolb23 [73]

Answer:

Oliver completed his training work in 50.25 hours

Step-by-step explanation:

we know that

1 day= 24 hours

1 hour=60 minutes

we have

2 days, 2 h, and 15 min

<u><em>Convert days to hours</em></u>

2 days=2(24)=48 hours

<u><em>Convert minutes to hour</em></u>

15 min=15(1/60)=1/4=0.25 h

so

2 days, 2 h, and 15 min=(48)+(2)+(0.25)=50.25 h

therefore

Oliver completed his training work in 50.25 hours

3 0
4 years ago
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
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