Answer:
The velocity in duct is 73.854 m/s.
Explanation:
Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 .
Also, P1 = Pressure in duct is 97kpa and P2 = Pressure at impact or stagnation point is 100kpa.
Using Bernoulli equation,
When air is flowing through duct,
When air is at stagnation point.
Comparing both the equation,
v=73.854 m/s.
Therefore, The velocity in duct is 73.854 m/s.
Answer:
J = 12.32kg*m/s
Explanation:
Assumptions: I'm assuming mis is m/s
Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.
When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:
mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°
For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):
The initial velocity is moving only in the horizontal direction, so:
The final velocity has an x and a y component:
Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):
To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:
Finally, substitute into the equation
J = 12.32kg*m/s